WBJEE · Physics · Gravitation
A mass \(M\) at rest is broken into two pieces having masses \(m\) and \((M-m) .\) The two masses are then separated by a distance \(r\) The gravitational force between them will be the maximum when the ratio of the masses \([m:(M-m)]\) of the two parts is
- A 1: 1
- B 1: 2
- C 1: 3
- D 1: 4
Answer & Solution
Correct Answer
(A) 1: 1
Step-by-step Solution
Detailed explanation
The gravitation force between two masses, \[ F=\frac{G m_{1} m_{2}}{r} \] here, \(\quad m_{1}=m\) and \[ \begin{array}{l} m_{2}=(M-m) \\ F=\frac{G m(M-m)}{r^{2}} \end{array} \] \(\therefore\) For maximum gravitational force, \(\frac{d F}{d m}=0\) \(\therefore\)…
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