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WBJEE · Chemistry · d and f Block Elements

The correct basicity order of the following lanthanide ions is

  1. A \(\mathrm{La}^{3+}>\mathrm{Lu}^{3 +}>\mathrm{Ce}^{3+}>\mathrm{Eu}^{3+}\)
  2. B \(\mathrm{Ce}^{3}>\mathrm{Lu}^{3+}>\mathrm{La}^{3+} > \mathrm{Eu}^{3 \mathrm{e}}\)
  3. C \(\mathrm{Lu}^{3 \cdot}>\mathrm{Ce}^{3}>\mathrm{Eu}^{3+}>\mathrm{La}^{3+}\)
  4. D \(\mathrm{La}^{3+}>\mathrm{Ce}^{3+}>\mathrm{Eu}^{3+}>\mathrm{Lu}^{3}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\mathrm{La}^{3+}>\mathrm{Ce}^{3+}>\mathrm{Eu}^{3+}>\mathrm{Lu}^{3}\)

Step-by-step Solution

Detailed explanation

As size of cation decreases, ionic character decreases, thus basicity also decreases Hence, correct order is \(\mathrm{La}^{3+}>\mathrm{Ce}^{3+}>\mathrm{Eu}^{3+}>\mathrm{Lu}^{3+}\)