WBJEE · Chemistry · d and f Block Elements
The correct basicity order of the following lanthanide ions is
- A \(\mathrm{La}^{3+}>\mathrm{Lu}^{3 +}>\mathrm{Ce}^{3+}>\mathrm{Eu}^{3+}\)
- B \(\mathrm{Ce}^{3}>\mathrm{Lu}^{3+}>\mathrm{La}^{3+} > \mathrm{Eu}^{3 \mathrm{e}}\)
- C \(\mathrm{Lu}^{3 \cdot}>\mathrm{Ce}^{3}>\mathrm{Eu}^{3+}>\mathrm{La}^{3+}\)
- D \(\mathrm{La}^{3+}>\mathrm{Ce}^{3+}>\mathrm{Eu}^{3+}>\mathrm{Lu}^{3}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{La}^{3+}>\mathrm{Ce}^{3+}>\mathrm{Eu}^{3+}>\mathrm{Lu}^{3}\)
Step-by-step Solution
Detailed explanation
As size of cation decreases, ionic character decreases, thus basicity also decreases Hence, correct order is \(\mathrm{La}^{3+}>\mathrm{Ce}^{3+}>\mathrm{Eu}^{3+}>\mathrm{Lu}^{3+}\)
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