WBJEE · Maths · Definite Integration
The value of integral \(\int_{-1}^1 \frac{|x+2|}{x+2} d x\) is
- A 1
- B 2
- C 0
- D -1
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
Hints : \(I=\int_{-1}^1 \frac{|x+2|}{x+2} d x \quad, \quad x+2=v \Rightarrow d x=d v\) \[ \therefore \mathrm{I}=\int_1^3 \frac{|v|}{V} d v=\int_1^3 \frac{v}{V} d v=\int_1^3 d v=2 \]
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