WBJEE · Maths · Straight Lines
A square with each side equal to 'a' above the \(x\)-axis and has one vertex at the origin. One of the sides passing through the origin makes an angle \(\alpha\left(0 \lt \alpha \lt \frac{\pi}{4}\right)\) with the positive direction of the axis. Equation of the diagonals of the square.
- A \(y(\cos \alpha-\sin \alpha)=x(\sin \alpha+\cos \alpha)\)
- B \(y(\cos \alpha+\sin \alpha)=x(\cos \alpha-\sin \alpha)\)
- C \(y(\sin \alpha+\cos \alpha)+x(\cos \alpha-\sin \alpha)=a\)
- D \(y(\cos \alpha-\sin \alpha)+x(\cos \alpha+\sin \alpha)=a\)
Answer & Solution
Correct Answer
(C) \(y(\sin \alpha+\cos \alpha)+x(\cos \alpha-\sin \alpha)=a\)
Step-by-step Solution
Detailed explanation
The parametric coordinate of one vertex of square is \((0+a \cos a, 0+a \sin a)\) Inclination of diagonal not passing through origin is \(135^{\circ}+\mathrm{a}\) \(\therefore\) equation of the diagonal which is not passing through origin is…
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