WBJEE · Maths · Trigonometric Ratios & Identities
The value of \(\frac{\cot 54^{\circ}}{\tan 36^{\circ}}+\frac{\tan 20^{\circ}}{\cot 70^{\circ}}\) is
- A 0
- B 2
- C 3
- D 1
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
Hints: \(\frac{\cot 54^{\circ}}{\tan 36^{\circ}}+\frac{\tan 20^{\circ}}{\cot 70^{\circ}}=\frac{\tan 36^{\circ}}{\tan 36^{\circ}}+\frac{\tan 20^{\circ}}{\tan 20^{\circ}}=1+1=2\)
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