WBJEE · Maths · Determinants
The system of equations \[ \begin{array}{l} \lambda x+y+3 z=0 \\ 2 x+\mu y-z=0 \\ 5 x+7 y+z=0 \end{array} \] has infinitely many solutions in \(R\). Then,
- A \(\lambda=2, \mu=3\)
- B \(\lambda=1, \mu=2\)
- C \(\lambda=1, \mu=3\)
- D \(\lambda=3, \mu=1\)
Answer & Solution
Correct Answer
(C) \(\lambda=1, \mu=3\)
Step-by-step Solution
Detailed explanation
Given, system of equations \[ \begin{array}{l} \lambda x+y+3 z=0 \\ 2 x+\mu y-z=0 \\ 5 x+7 y+z=0 \end{array} \] System has infinitely many solutions in \(R\), if \[ \left|\begin{array}{ccc} \lambda & 1 & 3 \\ 2 & \mu & -1 \\ 5 & 7 & 1 \end{array}\right|=0 \]…
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