WBJEE · Maths · Quadratic Equation
If the ratio of the roots of the equation \(\mathrm{px}^2+\mathrm{qx}+\mathrm{r}=0\) is \(a: b\), then \(\frac{\mathrm{ab}}{(\mathrm{a}+\mathrm{b})^2}=\)
- A \(\frac{\mathrm{p}^2}{\mathrm{qr}}\)
- B \(\frac{\mathrm{pr}}{\mathrm{q}^2}\)
- C \(\frac{q^2}{\mathrm{pr}}\)
- D \(\frac{\mathrm{pq}}{\mathrm{r}^2}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{pr}}{\mathrm{q}^2}\)
Step-by-step Solution
Detailed explanation
Hints: Let roots are \(a \alpha\) and \(b \alpha\) \(\Rightarrow(\mathrm{a}+\mathrm{b}) \alpha=\frac{-\mathrm{q}}{\mathrm{p}}\)…
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