WBJEE · Maths · Application of Derivatives
A bulb is placed at the centre of a circular track of radius \(10 \mathrm{~m}\). A vertical wall is erected touching the track at a point P. A man is running along the track with a speed of \(10 \mathrm{~m} / \mathrm{sec}\). Starting from \(\mathrm{P}\) the speed with which his shadow is running along the wall when he is at an angular distance of \(60^{\circ}\) from \(P\) is
- A \(30 \mathrm{~m} / \mathrm{sec}\)
- B \(40 \mathrm{~m} / \mathrm{sec}\)
- C \(60 \mathrm{~m} / \mathrm{sec}\)
- D \(80 \mathrm{~m} / \mathrm{sec}\)
Answer & Solution
Correct Answer
(B) \(40 \mathrm{~m} / \mathrm{sec}\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{\mathrm{v}}=\mathrm{r} \frac{\mathrm{d} \theta}{\mathrm{dt}}=10\) \(\tan \theta=\frac{\mathrm{y}}{\mathrm{r}}\) or, \(\mathrm{y}=\mathrm{r} \tan \theta\) or,…
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