WBJEE · Maths · Permutation Combination
The number of zeros at the end of 100! is
- A 21
- B 22
- C 23
- D 24
Answer & Solution
Correct Answer
(D) 24
Step-by-step Solution
Detailed explanation
\(\mathrm{E}_5(100 !)=\left[\frac{100}{5}\right]+\left[\frac{100}{25}\right]+\left[\frac{100}{125}\right]=20+4+0=24\)
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