WBJEE · Maths · Vector Algebra
\(\vec{a}, \vec{b}, \vec{c}\) are non-coplanar vectors and \(\lambda\) is a real number then the vectors \(\vec{a}+2 \vec{b}+3 \vec{c}, \lambda \vec{b}+4 \vec{c}\) and \((2 \lambda-1) \vec{c}\) are non-coplanar for
- A no value of \(\lambda\)
- B all except one value of \(\lambda\)
- C all except two values of \(\lambda\)
- D all values of \(\lambda\)
Answer & Solution
Correct Answer
(C) all except two values of \(\lambda\)
Step-by-step Solution
Detailed explanation
for co-planar : \(\left|\begin{array}{ccc}1 & 2 & 3 \\ 0 & \lambda & 4 \\ 0 & 0 & 2 \lambda-1\end{array}\right|=0 \Rightarrow \lambda=0, \frac{1}{2}\)
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