WBJEE · Chemistry · d and f Block Elements
Cupric compounds are more stable than their cuprous counterparts in solid state. This is because
- A the endothermic character of the 2nd IP of Cu is not so high
- B size of \(\mathrm{Cu}^{2+}\) is less than \(\mathrm{Cu}^{+}\)
- C \(\mathrm{Cu}^{2+}\) has stabler electronic contiguration as compared to \(\mathrm{Cu}^{+}\)
- D the lattice energy released for cupric compounds is much higher than \(\mathrm{Cu}^{+}\)
Answer & Solution
Correct Answer
(D) the lattice energy released for cupric compounds is much higher than \(\mathrm{Cu}^{+}\)
Step-by-step Solution
Detailed explanation
Electronic configurations of cuprous \(\left(\mathrm{Cu}^{*}\right)\) and cupric \(\left(\mathrm{Cu}^{2}{ }^{+}\right)\) ions are as follows…
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