WBJEE · Maths · Differential Equations
If \(x \frac{d y}{d x}+y=x \frac{f(x y)}{f^{\prime}(x y)}\), then \(|f(x y)|\) is equal to
- A \(\mathrm{Ce}^{\mathrm{x}^2 / 2}\)
- B \(\mathrm{Ce}^{\mathrm{x}^2}\)
- C \(\mathrm{Ce}^{2 x^2}\)
- D \(\mathrm{Ce}^{\mathrm{x}^2 / 3}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Ce}^{\mathrm{x}^2 / 2}\)
Step-by-step Solution
Detailed explanation
\(x \frac{d y}{d x}+y=x \frac{f(x y)}{f^{\prime}(x y)} \Rightarrow \frac{d(x y)}{d x}=x \frac{f(x y)}{f^{\prime}(x y)} \Rightarrow \frac{f^{\prime}(x y)}{f(x y)} d(x y)=x d x \Rightarrow \ln |f(x y)|=\frac{x^2}{2}+k \Rightarrow f(x y)=C e^{\frac{x^2}{2}}\)
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