WBJEE · Maths · Definite Integration
The average ordinate of \(y=\sin x\) over \([0, \pi]\) is
- A \(\frac{2}{\pi}\)
- B \(\frac{3}{\pi}\)
- C \(\frac{4}{\pi}\)
- D \(\pi\)
Answer & Solution
Correct Answer
(A) \(\frac{2}{\pi}\)
Step-by-step Solution
Detailed explanation
Hint : As \(\sin x\) is a continuous function in \([0, \pi]\) Average ordinate will be \(=\frac{1}{\pi-0} \int_0^\pi \sin x d x=\frac{[-\cos x]_0^\pi}{\pi}=\frac{2}{\pi}\)
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