WBJEE · Maths · Circle
The angle of intersection between the curves \(y=[|\sin x|+|\cos x|]\) and \(x^{2}+y^{2}=10,\) where \([x]\) denotes the greatest integer \(\leq x,\) is
- A \(\tan ^{-1} 3\)
- B \(\tan ^{-1}(-3)\)
- C \(\tan ^{-1} \sqrt{3}\)
- D \(\tan ^{-1}(1 / \sqrt{3})\)
Answer & Solution
Correct Answer
(A) \(\tan ^{-1} 3\)
Step-by-step Solution
Detailed explanation
Given, \(y=\left[|\sin x|+|\cos x|\right.\) land \(x^{2}+y^{2}=10\) We know that \((|\sin x|+|\cos x|) \in[1, \sqrt{2}]\) \(\therefore\) \[ y=1 \] The point of intersection of given curve is…
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