WBJEE · Maths · Parabola
A line passing through the point of intersection of \(x+y=4\) and \(x-y=2\) makes an angle \(\tan ^{-1}\left(\frac{3}{4}\right)\) with the \(X\) -axis. It intersects the parabola \(y^{2}=4(x-3)\) at points \(\left(x_{1}, y_{1}\right)\) and \(\left(x_{2}, y_{2}\right),\) respectively. Then \(\left|x_{1}-x_{2}\right|\) is equal to
- A \(\frac{16}{9}\)
- B \(\frac{32}{9}\)
- C \(\frac{40}{9}\)
- D \(\frac{80}{9}\)
Answer & Solution
Correct Answer
(B) \(\frac{32}{9}\)
Step-by-step Solution
Detailed explanation
Given equations are \(x+y=4 ...(i)\) and \(\quad x-y=2\) ...(ii) From Eqs. (i) and \((ii),\) we get \(x=3\) and \(y=1\) The line through this point making an angle tan \(^{-1} \frac{3}{4}\) with the \(X\) -axis is…
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