WBJEE · Maths · Statistics
Standard deviation of \(n\) observations \(a_{1}, a_{2}, a_{3}, \ldots, a_{n}\) is \({\sigma} .\) Then, the standard deviation of the observations \(\lambda a_{1}, \lambda a_{2}, \ldots, \lambda a_{n}\) is
- A \(\lambda {\sigma}\)
- B \(-\lambda \sigma\)
- C \(|\lambda| \sigma\)
- D \(\lambda^{n} \boldsymbol{\sigma}\)
Answer & Solution
Correct Answer
(C) \(|\lambda| \sigma\)
Step-by-step Solution
Detailed explanation
Let \(x_{i}=a_{1}, a_{2}, a_{3}, \ldots, a_{n}\) and \(y_{i}=\lambda a_{1}, \lambda a_{2}, \lambda a_{3}, \ldots, \lambda a_{n-}\) \[ y_{i}=\lambda x_{i} \] \(\because\) \(\begin{aligned} \bar{y} &=\frac{\Sigma y_{i}}{N} \\ &=\frac{\Sigma \lambda x_{i}}{n} \end{aligned}\)…
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