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WBJEE · Maths · Limits

Let \(t_{n}\) denotes the nth term of the infinite series \(\frac{1}{1 !}+\frac{10}{2 !}+\frac{21}{3 !}+\frac{34}{4 !}+\frac{49}{5 !}+\ldots .\) Then \(\lim _{n \rightarrow \infty} t_{n}\) is

  1. A \(e\)
  2. B \(0\)
  3. C \(e^{2}\)
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(B) \(0\)

Step-by-step Solution

Detailed explanation

Let \(\quad S=1+10+21+34+49+\ldots+t_{n}^{\prime}\) and \(S=1+10+21+34+\ldots+t_{n}^{\prime}\) \(0=1+9+11+13+15+\ldots-t_{n}^{\prime}\)…