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The correct order of boiling point of the given aqueous solution is
- A \(1 \mathrm{~N} \mathrm{KNO}_3>1 \mathrm{~N} \mathrm{NaCl} >1 \mathrm{~N} \mathrm{CH}_3 \mathrm{COOH} >1 \mathrm{~N} \text { sucrose }\)
- B \(1 \mathrm{~N} \mathrm{KNO}_3=1 \mathrm{~N} \mathrm{NaCl} >1 \mathrm{~N} \mathrm{CH}_3 \mathrm{COOH} >1 \mathrm{~N} \text { sucrose }\)
- C Same for all
- D \(1 \mathrm{~N} \mathrm{KNO}_3=1 \mathrm{~N} \mathrm{NaCl} =1 \mathrm{~N} \mathrm{CH}_3 \mathrm{COOH} >1 \mathrm{~N} \text { sucrose }\)
Answer & Solution
Correct Answer
(B) \(1 \mathrm{~N} \mathrm{KNO}_3=1 \mathrm{~N} \mathrm{NaCl} >1 \mathrm{~N} \mathrm{CH}_3 \mathrm{COOH} >1 \mathrm{~N} \text { sucrose }\)
Step-by-step Solution
Detailed explanation
Hint : Elevation in boiling point \(\propto\) No. of solute particles \(\mathrm{KNO}_3\) (strong electrolyte); \(\mathrm{KNO}_{3(\text { (aq) }} \rightarrow \mathrm{K}_{(\mathrm{aq})}^{+}+\mathrm{NO}_{3 \text { (aq) }}^{-}\) NaCl (Strong electrolyte);…
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