WBJEE · Maths · Circle
Let \(C_{1}\) and \(C_{2}\) denote the centres of the circles \(x^{2}+y^{2}=4\) and \((x-2)^{2}+y^{2}=1\) respectively and let \(P\) and \(Q\) be their points of intersection.Then, the areas of \(\Delta C_{1} P Q\) and \(C_{2} P Q\) are in the ratio
- A 3: 1
- B 5: 1
- C 7: 1
- D 9: 1
Answer & Solution
Correct Answer
(C) 7: 1
Step-by-step Solution
Detailed explanation
\(x^{2}+y^{2}=4\) \[ \begin{array}{l} (x-2)^{2}+y^{2}=1 \\ C_{1}=(0,0), C_{2}=(2,0) \end{array} \] On solving Eqs. (i) and (ii), we get…
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