WBJEE · Maths · Binomial Theorem
Let \(a_n\) denote the term independent of \(x\) in the expansion of \(\left[x+\frac{\sin (1 / n)}{x^2}\right]^{3 n}\), then \(\lim _{n \rightarrow \infty} \frac{\left(a_n\right) n!}{{ }^{3 n} P_n}\) equals
- A \(0\)
- B \(1\)
- C e
- D \(\frac{\mathrm{e}}{\sqrt{3}}\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(\left[x+\frac{\sin (1 / n)}{x^2}\right]^{3 n}\) \(\begin{aligned} & T_{r+1}={ }^{3 n} C_r(x)^{3 n-r}\left(\frac{\sin (1 / n)}{x^2}\right)^r \\ & ={ }^{3 n} C_r(x)^{3 n-3 r}(\sin (1 / n))^r \\ & r=n \end{aligned}\)…
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