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WBJEE · Maths · Probability

Three numbers are chosen at random from 1 to 20 . The probability that they are consecutive is

  1. A \(\frac{1}{190}\)
  2. B \(\frac{1}{120}\)
  3. C \(\frac{3}{190}\)
  4. D \(\frac{5}{190}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{3}{190}\)

Step-by-step Solution

Detailed explanation

Hints: Total number of cases ; \({ }^{20} \mathrm{C}_3=\frac{20 \times 19 \times 18}{2 \times 3}=20 \times 19 \times 3=1140\) Total number of favourable cases \(=18\) \(\therefore\) Required probability \(=\frac{18}{1140}=\frac{3}{190}\)