WBJEE · Maths · Straight Lines
In \(\triangle A B C\), co-ordinates of \(A\) are \((1,2)\) and the equation of the medians through \(B\) and \(C\) are \(x+y=5\) and \(x=4\) respectively. Then the midpoint of \(B C\) is
- A \(\left(5, \frac{1}{2}\right)\)
- B \(\left(\frac{11}{2}, 1\right)\)
- C \(\left(11, \frac{1}{2}\right)\)
- D \(\left(\frac{11}{2}, \frac{1}{2}\right)\)
Answer & Solution
Correct Answer
(D) \(\left(\frac{11}{2}, \frac{1}{2}\right)\)
Step-by-step Solution
Detailed explanation
Let \(\mathrm{D}, \mathrm{E}, \mathrm{F}\) be midpoint of \(\mathrm{BC}, \mathrm{AC}\) and AB respectively. According to question equation of \(B E: x+y=5\) Equation of \(C F\) \(x=4\) \(\therefore\) Centroid \((4,1)\) Let point \(D\) be \((\alpha, \beta)\) by section formula,…
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