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WBJEE · Maths · Quadratic Equation

If \(\alpha, \beta\) be the roots of \(x^2-a(x-1)+b=0\), then the value of \(\frac{1}{\alpha^2-a \alpha}+\frac{1}{\beta^2-a \beta}+\frac{2}{a+b}\)

  1. A \(\frac{4}{a+b}\)
  2. B \(\frac{1}{a+b}\)
  3. C 0
  4. D -1
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Answer & Solution

Correct Answer

(C) 0

Step-by-step Solution

Detailed explanation

\[ \begin{aligned} & \text { Hints }: x^2-a x=a+3 \quad \alpha \beta=a+b \\ & \alpha+\beta=a \\ & \alpha^2-a \alpha=-(a+b) \\ & \beta^2-a \alpha=-(a+b) \\ &-\frac{1}{a+b}-\frac{1}{a+b}+\frac{2}{a+b}=0 \end{aligned} \]
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