WBJEE · Maths · Quadratic Equation
In a \(\triangle A B C\), tan \(A\) and \(\tan B\) are the roota \(p q\left(x^{2}+1\right)=r^{2} x\) Then, \(\Delta A B C\) is
- A a right angled triangle
- B an acute angled triangle
- C an obtuse angled triangle
- D an equilateral triangle
Answer & Solution
Correct Answer
(A) a right angled triangle
Step-by-step Solution
Detailed explanation
Given equation can be rewritten as \(x^{2}-\frac{r^{2}}{p q} x+1=0\) \(\therefore \quad \tan A+\tan B=\frac{r^{2}}{p q}\) and \(\tan A \tan B=1\) We know, \(A+B+C=180^{\circ}\) \(\Rightarrow \quad(A+B)=180^{\circ}-C\)…
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