WBJEE · Maths · Differentiation
If the transformation \(z=\log \tan \frac{x}{2}\) reduces the differential equation \(\frac{d^2 y}{d x^2}+\cot x \frac{d y}{d x}+4 y \operatorname{cosec}{ }^2 x=0\) into the form \(\frac{d^2 y}{d z^2}+k y=0\) then \(k\) is equal to
- A \(-4\)
- B 4
- C 2
- D \(-2\)
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
\(\frac{d^2 y}{d z^2}=\frac{d}{d z}\left(\frac{d y}{d z}\right)=\frac{d}{d z}\left(\frac{\frac{d y}{d x}}{\frac{d z}{d x}}\right)\) \(=\frac{d}{d z}\left(\frac{\frac{d y}{d x}}{\frac{1}{\sin x}}\right) \quad\left(\because \frac{d z}{d x}=\frac{1}{\sin x}\right)\)…
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