WBJEE · Maths · Quadratic Equation
If \(a, b\) and \(c\) are in arithmetic progression, then the roots of the equation \(a x^{2}-2 h x+c=0\) are
- A 1 and \(\frac{c}{a}\)
- B \(-\frac{1}{a}\) and \(-c\)
- C -1 and \(-\frac{c}{a}\)
- D -2 and \(-\frac{c}{2 a}\)
Answer & Solution
Correct Answer
(A) 1 and \(\frac{c}{a}\)
Step-by-step Solution
Detailed explanation
Since, \(a, b\) and \(c\) are in \(\mathrm{AP}\). \(\therefore\) \(2 b=a+c\) Given, quadratic equation, \(a x^{2}-2 b x+c=0\) \(\Rightarrow \quad a x^{2}-(a+c) x+c=0\) \(2 b=a+c)\) \(\Rightarrow \quad a x^{2}-a x-c x+c=0\)…
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