WBJEE · Chemistry · Solid State
If three elements \(A, B, C\) crystalise in a cubic solid lattice with \(B\) atoms at the cubic centres, \(C\) atoms at the centre of edges and \(A\) atoms at the corners, then formula of the compound is
- A \(\mathrm{AB}_3 \mathrm{C}\)
- B \(\mathrm{A}_3 \mathrm{BC}\)
- C \(\mathrm{ABC}_3\)
- D ABC
Answer & Solution
Correct Answer
(C) \(\mathrm{ABC}_3\)
Step-by-step Solution
Detailed explanation
Number of A atoms \(=\frac{1}{8} \times 8=1\) Number of \(C\) atoms \(=\frac{1}{4} \times 12=3\) Number of B atom = 1 Hence \(\mathrm{ABC}_3\)
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