WBJEE · Maths · Definite Integration
If \(f(x)=f(a-x)\) then \(\int_0^a x f(x) d x\) is equal to
- A \(\int_0^a f(x) d x\)
- B \(\frac{a^2}{2} \int_0^{\mathrm{a}} \mathrm{f}(\mathrm{x}) \mathrm{dx}\)
- C \(\frac{a}{2} \int_0^a f(x) d x\)
- D \(-\frac{a}{2} \int_0^{\mathrm{a}} f(x) d x\)
Answer & Solution
Correct Answer
(C) \(\frac{a}{2} \int_0^a f(x) d x\)
Step-by-step Solution
Detailed explanation
Hints : \(f(x)=f(a-x), I=\int_0^a x f(x) d x=\int_0^a(a-x) f(a-x) d x\) \[ \begin{aligned} & =\int_0^a(a-x) f(x) d x=a \int_0^a f(x) d x-I \\ & \therefore 2 I=a \int_0^a f(x) d x \Rightarrow I=\frac{a}{2} \int_0^a f(x) d x \end{aligned} \]
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