WBJEE · Maths · Straight Lines
If \(a>0, b>0\) then the maximum area of the parallelogram whose three vertices are \(O(0,0), A(a \cos \theta, b \sin \theta)\) and \(\mathrm{B}(\mathrm{a} \cos \theta,-\mathrm{b} \sin \theta)\) is
- A ab when \(\theta=\pi / 4\)
- B 3 ab when \(\theta=\pi / 4\)
- C ab when \(\theta=\pi / 2\)
- D \(2 \mathrm{ab}\)
Answer & Solution
Correct Answer
(A) ab when \(\theta=\pi / 4\)
Step-by-step Solution
Detailed explanation
Area \(\mathrm{OABC}=2 \times\) area \(\triangle \mathrm{OAB}\)…
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