WBJEE · Maths · Three Dimensional Geometry
If from a point \(\mathrm{P}(\mathrm{a}, \mathrm{b}, \mathrm{c})\), perpendiculars \(\mathrm{PA}\) and \(\mathrm{PB}\) are drawn to \(\mathrm{YZ}\) and \(\mathrm{ZX}\) planes respectively, then the equation of the plane \(\mathrm{OAB}\) is
- A \(b c x+\) cay \(+a b z=0\)
- B bcx \(+\) cay \(-a b z=0\)
- C \(\mathrm{bcx}-\mathrm{cay}+\mathrm{abz}=0\)
- D bcx - cay - abz = 0
Answer & Solution
Correct Answer
(B) bcx \(+\) cay \(-a b z=0\)
Step-by-step Solution
Detailed explanation
\(\mathrm{A}(\mathrm{o}, \mathrm{b}, \mathrm{c}) \mathrm{B}(\mathrm{a}, \mathrm{o}, \mathrm{c}), \mathrm{O}(\mathrm{o}, \mathrm{o}, \mathrm{o})\) Perpendicular vector is \(\overrightarrow{\mathrm{OA}} \times \overrightarrow{\mathrm{OB}}\)…
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