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WBJEE · Maths · Quadratic Equation

For real \(x\), the greatest value of \(\frac{x^{2}+2 x+4}{2 x^{2}+4 x+9}\) is

  1. A 1
  2. B -1
  3. C \(\frac{1}{2}\)
  4. D \(\frac{1}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

Let \(y=\frac{x^{2}+2 x+4}{2 x^{2}+4 x+9}\) \(\Rightarrow 2 x^{2} y+4 x y+9 y=x^{2}+2 x+4\) \(\Rightarrow(2 y-1) x^{2}+(4 y-2) x+9 y-4=0\) \(\Rightarrow x=\frac{-(4 y-2) \pm \sqrt{(4 y-2)^{2}-4(2 y-1)(9 y-4)}}{2(2 y-1)}\) Since, \(x\) is real number.…