WBJEE · Maths · Trigonometric Ratios & Identities
For \(0 \leq P, Q \leq \frac{\pi}{2},\) if \(\sin P+\cos Q=2\), then the
value of \(\tan \left(\frac{\vec{P}+Q}{2}\right)\) is equal to
- A 1
- B \(\frac{1}{\sqrt{2}}\)
- C \(\frac{1}{2}\)
- D \(\frac{\sqrt{3}}{2}\)
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
Given, \(0 \leq P, Q \leq \frac{\pi}{2}\) and \(\sin P+\cos Q=2\) This equation hold only when, \(\quad P=\frac{\pi}{2}\) and \(\quad Q=0\) \(\mathrm{LHS}=\sin P+\cos Q=\sin \frac{\pi}{2}+\cos 0\) \[ =1+1=2=\mathrm{RHS} \]…
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