WBJEE · Maths · Indefinite Integration
\(\int \frac{\sin ^8 x-\cos ^8 x}{1-2 \sin ^2 x \cos ^2 x} d x\)
- A \(-\frac{1}{2} \sin 2 x+C\)
- B \(\frac{1}{2} \sin 2 \mathrm{x}+\mathrm{C}\)
- C \(\frac{1}{2} \sin x+C\)
- D \(-\frac{1}{2} \sin x+C\)
Answer & Solution
Correct Answer
(A) \(-\frac{1}{2} \sin 2 x+C\)
Step-by-step Solution
Detailed explanation
Hints: \(\int\left(\sin ^2 x-\cos ^2 x\right) d x=-\int \cos ^{2 x} d x=-\frac{1}{2} \sin 2 x+C\)
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