WBJEE · Maths · Determinants
If \(a_{r}=(\cos 2 r \pi+i \sin 2 r \pi)^{1 / 9}\), then the value of
\(\left|\begin{array}{lll}a_{1} & a_{2} & a_{3} \\ a_{4} & a_{5} & a_{6} \\ a_{7} & a_{8} & a_{9}\end{array}\right|\) is equal to
- A 1
- B -1
- C 0
- D 2
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
We have, \(a_{r}=(\cos 2 r \pi+i \sin 2 r \pi)^{1 / 9}=e^{\frac{2 r \pi i}{9}}\) Now,…
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