WBJEE · Maths · Trigonometric Ratios & Identities
\(\tan \left[\frac{\pi}{4}+\frac{1}{2} \cos ^{-1}\left(\frac{a}{b}\right)\right]+\tan \left[\frac{\pi}{4}-\frac{1}{2} \cos ^{-1}\left(\frac{a}{b}\right)\right]\) is equal to
- A \(\frac{2 a}{b}\)
- B \(\frac{2 b}{a}\)
- C \(\frac{a}{b}\)
- D \(\frac{b}{a}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 b}{a}\)
Step-by-step Solution
Detailed explanation
Hints : Let \(\frac{1}{2} \cos ^{-1}\left(\frac{a}{b}\right)=\theta\), then \(\cos 2 \theta=\frac{a}{b}\)…
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