WBJEE · Chemistry · Hydrocarbons
The total number of alkyl bromides (including stereoismers) formed in the reaction \(\mathrm{Me}_{3} \mathrm{C}-\mathrm{CH}=\mathrm{CH}_{2}+\mathrm{HBr} \rightarrow\) will be
- A 1
- B 2
- C 3
- D No bromide forms
Answer & Solution
Correct Answer
(C) 3
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