WBJEE · Physics · Alternating Current
An altermating current is flowing through a series \(L-C - R\) circuit. It is found that the current reaches a value of \(1 \mathrm{mA}\) at both \(200 \mathrm{Hz}\) and \(800 \mathrm{Hz}\) frequency. What is the resonance frequency of the circuit?
- A \(600 \mathrm{Hz}\)
- B \(300 \mathrm{Hz}\)
- C \(500 \mathrm{Hz}\)
- D \(400 \mathrm{Hz}\)
Answer & Solution
Correct Answer
(D) \(400 \mathrm{Hz}\)
Step-by-step Solution
Detailed explanation
\(\because\) Resonance frequency, \(f_{0}=\sqrt{f_{1} f_{2}}\) \[ =\sqrt{200 \times 800}=400 \mathrm{Hz} \]
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