WBJEE · Chemistry · Chemical Kinetics
The kinetic study of a reaction like \(v A \rightarrow P\) at \(300 \mathrm{K}\) provides the following curve, where concentration is taken in mol \(\mathrm{dm}^{-3}\) and time in min.
Identify the correct order \((n)\) and rate constant \((k)\)
- A \(n=0, k=4.0 \mathrm{mol} \mathrm{dm}^{-3} \mathrm{min}^{-1}\)
- B \(n=1 / 2, k=2.0 \mathrm{mol}^{1 / 2} \mathrm{dm}^{-3 / 2} \mathrm{min}^{-1}\)
- C \(n=1, k=80 \mathrm{min}^{-1}\)
- D \(n=2, k=16.0 \mathrm{dm}^{3} \mathrm{mol}^{-1} \mathrm{min}^{-1}\)
Answer & Solution
Correct Answer
(D) \(n=2, k=16.0 \mathrm{dm}^{3} \mathrm{mol}^{-1} \mathrm{min}^{-1}\)
Step-by-step Solution
Detailed explanation
From the given graph Slope \(=\frac{(\text { rate })^{1 / 2}}{[A]}=4\) \(\because\) rate \((r)=k[A]^{n}\) Where, \(k=\) rate constant \([A]=\) concentration at time \(t\) (in min). \(n=\) order. According to the graph \((n=2)\)…
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