WBJEE · Chemistry · States of Matter
The compressibility factor \((Z)\) of one mole of a van der Waals' gas of negligible ' \(a\) ' value is
- A 1
- B \(\frac{b p}{R T}\)
- C \(1+\frac{b p}{R T}\)
- D \(1-\frac{b p}{R T}\)
Answer & Solution
Correct Answer
(C) \(1+\frac{b p}{R T}\)
Step-by-step Solution
Detailed explanation
van der Waals' equation is \(\left(p+\frac{a}{V^{2}}\right)(V-b)=R T\) (for 1 mole) If \(a\) is negligible, \(p+\frac{a}{V^{2}} \approx p\) \[ p(V-b)=R T \Rightarrow p V-p b=R T \] or \(\frac{p V}{R T}-\frac{p b}{R T}=1 \Rightarrow \frac{p V}{R T}=1+\frac{p b}{R T}\)
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