WBJEE · Chemistry · Chemical Bonding and Molecular Structure
The boiling points of \(\mathrm{HF}, \mathrm{HCl}, \mathrm{HBr}\) and \(\mathrm{HI}\) follow the order
- A HF \(>\mathrm{HCl}>\mathrm{HBr}>\mathrm{Hl}\)
- B \(\mathrm{HF}>\mathrm{Hl}>\mathrm{HBr}>\mathrm{HCl}\)
- C \(\mathrm{Hl}>\mathrm{HBr}>\mathrm{HCl}>\mathrm{H}\)
- D \(\mathrm{HCl}>\mathrm{HF}>\mathrm{HBr}>\mathrm{Hl}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{HF}>\mathrm{Hl}>\mathrm{HBr}>\mathrm{HCl}\)
Step-by-step Solution
Detailed explanation
Due to hydrogen bonding, HF shows highest boiling point. Thereafter van der Waals' force decide the boiling point. Larger the size or molecules mass, greater is the van der Waals' forces. Hence, higher is the boiling point. \(\because\) van der Waals' forces is more for HI than…
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