WBJEE · Chemistry · Solid State
In a close-packed body-centred cubic lattice of potassium, the correct relation between the atomic radius \((r)\) of potassium and the edge-length of the cube is
- A \(r=\frac{a}{\sqrt{2}}\)
- B \(r=\frac{a}{\sqrt{3}}\)
- C \(r=\frac{\sqrt{3}}{2} a\)
- D \(r=\frac{\sqrt{3}}{4} a\)
Answer & Solution
Correct Answer
(D) \(r=\frac{\sqrt{3}}{4} a\)
Step-by-step Solution
Detailed explanation
\(\because\) For be packing, \(\sqrt{3} a=4 r \therefore r=\frac{\sqrt{3}}{4} \cdot a\) where \(a=\) edge length \(r=\) radius of lattice sphere
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