ExamBro
ExamBro
WBJEE · Chemistry · Redox Reactions

If the molecular wt. of \(\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3\) and \(\mathrm{I}_2\) are \(\mathrm{M}_1\) and \(\mathrm{M}_2\) respectively, then what will be the equivalent wt. of \(\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3\) and \(\mathrm{I}_2\) in the following reaction?
\(2 \mathrm{~S}_2 \mathrm{O}_3^{2-}+\mathrm{I}_2 \longrightarrow \mathrm{S}_4 \mathrm{O}_6^{2-}+2 \mathrm{I}^{-}\)

  1. A \(\mathrm{M}_1, \mathrm{M}_2\)
  2. B \(\mathrm{M}_1, \mathrm{M}_2 / 2\)
  3. C \(2 \mathrm{M}_1, \mathrm{M}_2\)
  4. D \(\mathrm{M}_1, 2 \mathrm{M}_2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{M}_1, \mathrm{M}_2 / 2\)

Step-by-step Solution

Detailed explanation

Hints: \(\begin{aligned} & \text { n.f. }\left(\mathrm{S}_2 \mathrm{O}_3^{2-}\right)=1, \text { Equivalent mass }=\frac{\mathrm{M}_1}{1}=\mathrm{M}_1 \\ & \mathrm{n} \mathrm{f} .\left(\mathrm{I}_2\right)=2, \quad \text { Equivalent mass }=\frac{\mathrm{M}_2}{2} \end{aligned}\)