WBJEE · Chemistry · Structure of Atom
For the reaction \(14 N+\alpha \longrightarrow{}^{17} O+p\), \(1.16 \mathrm{MeV}(\) Mass equivalent \(=0.00124 \mathrm{amu})\) of energy is absorbed. Mass on the reactant side is \(18.00567\) amu and proton mass \(=1.00782 \mathrm{amu}\). The atomic mass of \({ }^{17} \mathrm{O}\) will be
- A \(17.0044 \mathrm{amu}\)
- B \(16.9991 \mathrm{amu}\)
- C \(17.0114 \mathrm{amu}\)
- D \(16.9966 \mathrm{amu}\)
Answer & Solution
Correct Answer
(B) \(16.9991 \mathrm{amu}\)
Step-by-step Solution
Detailed explanation
\({ }^{14} \mathrm{~N}_{7}+{ }_{2}^{4} \mathrm{He} \rightarrow{ }^{17} \mathrm{O}_{8}+{ }_{1}^{1} \mathrm{H}\) mass defect \(=0.00124 \mathrm{amu}\)…
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