WBJEE · Chemistry · Electrochemistry
At a particular temperature. the ratio of equivalent conductance to specific conductance of a 0.01 N NaCl solution is
- A \(10^{5} \mathrm{cm}^{3}\)
- B \(10^{3} \mathrm{cm}^{3}\)
- C \(10 \mathrm{cm}^{3}\)
- D \(10^{5} \mathrm{cm}^{2}\)
Answer & Solution
Correct Answer
(A) \(10^{5} \mathrm{cm}^{3}\)
Step-by-step Solution
Detailed explanation
As we know that, Equivalent conductance, ( \(\lambda\) ) \(=\frac{\text { Specific conductance }(K) \times 1000}{\text { Concentration }}\) or. \(\quad \frac{\lambda}{K}=\frac{1000}{\text { conc. }}\) Or.…
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