WBJEE · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
Among the following observations, the correct one that differentiates between \(\mathrm{SO}_{3}^{2-}\) and \(\mathrm{SO}_{4}^{2-}\) is
- A both form precipitate with \(\mathrm{BaCl}_{2}, \mathrm{SO}_{3}^{2-}\) dissolves in \(\mathrm{HCl}\) but \(\mathrm{SO}_{4}^{2-}\) does not
- B \(\mathrm{SO}_{3}^{2-}\) forms precipitate with \(\mathrm{BaCl}_{2}, \mathrm{SO}_{4}^{2-}\) does not
- C \(\mathrm{SO}_{4}^{2-}\) forms precipitate with \(\mathrm{BaCl}_{2}, \mathrm{SO}_{3}^{2-}\) does not
- D both form precipitate with \(\mathrm{BaCl}_{2}, \mathrm{SO}_{4}^{2-}\) dissolves in HCl but \(S O_{3}^{2-}\) does not
Answer & Solution
Correct Answer
(A) both form precipitate with \(\mathrm{BaCl}_{2}, \mathrm{SO}_{3}^{2-}\) dissolves in \(\mathrm{HCl}\) but \(\mathrm{SO}_{4}^{2-}\) does not
Step-by-step Solution
Detailed explanation
\(\mathrm{SO}_{3}^{2-}\) and \(\mathrm{SO}_{4}^{2-}\) when treated with \(\mathrm{BaCl}_{2}\), give white ppt of \(BaSO_{3}\) and \(BaSO_{4}\) respectively.…
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