WBJEE · Chemistry · Structure of Atom
Which one of the following electronic arrangements is absurd?
- A \(n=3, l=1, m=-1\)
- B \(n=3, l=0, m=0\)
- C \(n=2,l=0, m=-1\)
- D \(n=2, l=1, m=0\)
Answer & Solution
Correct Answer
(C) \(n=2,l=0, m=-1\)
Step-by-step Solution
Detailed explanation
The three quantum numbers \(n, l\) and \(m\) that describe an orbital has integer values of 0,1,2,3 and so on. The electronic arrangement of option (c) is absurd because \[ \begin{array}{l} n=2 \\ l=0 \\ m=0 \end{array} \] To sum up, where \(n=2, l=0, m=0\) Hence, for \(l=0,\)…
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