TS EAMCET · Physics · Thermodynamics
When the temperature of a gas in a closed vessel is increased by \(2.4^{\circ} \mathrm{C}\), its pressure increases by \(0.5 \%\). The initial temperature of the gas is
- A \(120^{\circ} \mathrm{C}\)
- B \(240^{\circ} \mathrm{C}\)
- C \(480^{\circ} \mathrm{C}\)
- D \(207^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(D) \(207^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(\frac{P_1}{T_1} = \frac{P_2}{T_2}\) \(\frac{P_1}{T_1} = \frac{P_1 + 0.005 P_1}{T_1 + 2.4}\) \(\frac{1}{T_1} = \frac{1.005}{T_1 + 2.4}\) \(T_1 + 2.4 = 1.005 T_1\) \(0.005 T_1 = 2.4\) \(T_1 = \frac{2.4}{0.005} = 480 \, \mathrm{K}\)…
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