TS EAMCET · Physics · Waves and Sound
Two sound waves each of intensity I are superimposed. If the phase difference between the waves is \(\frac{\pi}{2}\), then the intensity of the resultant wave is
- A 2 I
- B 3 I
- C 4 I
- D I
Answer & Solution
Correct Answer
(A) 2 I
Step-by-step Solution
Detailed explanation
\(I_{res} = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos(\phi)\) \(I_{res} = I + I + 2\sqrt{I \cdot I} \cos(\frac{\pi}{2})\) \(I_{res} = 2I + 2I \cdot 0\) \(I_{res} = 2I\)
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