TS EAMCET · Physics · Dual Nature of Matter
Two photons of energies twice and thrice the work function of a metal are incident on the metal surface. Then, the ratio of maximum velocities of the photoelectrons emitted in the two cases respectively, is
- A \(\sqrt{2}: 1\)
- B \(\sqrt{3}: 3\)
- C \(\sqrt{3}: \sqrt{2}\)
- D \(1: \sqrt{2}\)
Answer & Solution
Correct Answer
(D) \(1: \sqrt{2}\)
Step-by-step Solution
Detailed explanation
Let the work function of the metal be \(W\) Then energy of Ist photon \(E_1=2 W\) Energy of IInd photon \(E_2=3 \mathrm{~W}\) Maximum KE of photoelectron \[ (\mathrm{KE})_{\max }=E-W \] (Einstein's equation) For first photon \(\left(\mathrm{KE}_1\right)_{\max }=2 W-W=W\) For…
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