TS EAMCET · Physics · Capacitance
Three capacitors of capacitances \(10 \mu \mathrm{~F}, 5 \mu \mathrm{~F}\) and \(20 \mu \mathrm{~F}\) are connected in series with a 14 V dc supply. The charge on \(5 \mu \mathrm{~F}\) capacitor is
- A \(20 \mu \mathrm{C}\)
- B \(40 \mu \mathrm{C}\)
- C \(70 \mu \mathrm{C}\)
- D \(2.8 \mu \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(40 \mu \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Charge given by DC supply, \(\mathrm{Q}=\mathrm{C}_{\text {eq }} \mathrm{V}\) \(\frac{1}{C_{e q}}=\frac{1}{10}+\frac{1}{5}+\frac{1}{20}\) or, \(\mathrm{C}_{\mathrm{eq}}=\frac{20}{7}\) \(\therefore Q=\frac{20}{7} \times 14=40 \mu \mathrm{c}\) As capacitors are connected in series…
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